Buster bet math blackjack

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A lower/negative count favors the dealer, as there are more low cards left in the deck that can complete the dealer's hand, not bust it.

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Per the Hi-Lo count, a higher count -> relatively more 10s in the deck -> higher chance of the dealer busting when showing an up card of 4,5,6 for example. The dealer should be more likely to bust when the count is *high*, not low. This doesn't make a lot of intuitive sense - maybe I'm missing something. If someone can do the math utilizing both the Hi-Lo count, and the Uston APC count system, I'd be forever grateful!! I understand the count would need to be higher for this side bet to be profitable when the dealer is showing a 2 versus a 6, and is probably never a profitable bet when the dealer is showing a 7-Ace - but what are those thresholds?!īust Bonus payouts (format: Dealer's up card, bust(non-suited), bust (suited)): I'm wondering what the true count would need to reach before the odds for this side bet swing in the player's favor. This side bet seems like a profitable one to make when the true count reaches a certain threshold (at least for dealer up cards 2-6). Hi all, I've noticed many casinos in my area offer a side bet called 'Bust Bonus' (the player gets paid when they make this side bet and the dealer ends up busting his/her hand).

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